2(5a)^2+4=0

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Solution for 2(5a)^2+4=0 equation: 



2(5a)^2+4=0

a = 25; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·25·4
Δ = -400
Delta is less than zero, so there is no solution for the equation

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